Solve for A
\left\{\begin{matrix}A=\frac{X}{2B}\text{, }&B\neq 0\\A\in \mathrm{R}\text{, }&X=0\text{ and }B=0\end{matrix}\right.
Solve for B
\left\{\begin{matrix}B=\frac{X}{2A}\text{, }&A\neq 0\\B\in \mathrm{R}\text{, }&X=0\text{ and }A=0\end{matrix}\right.
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X=2AB
Combine AB and AB to get 2AB.
2AB=X
Swap sides so that all variable terms are on the left hand side.
2BA=X
The equation is in standard form.
\frac{2BA}{2B}=\frac{X}{2B}
Divide both sides by 2B.
A=\frac{X}{2B}
Dividing by 2B undoes the multiplication by 2B.
X=2AB
Combine AB and AB to get 2AB.
2AB=X
Swap sides so that all variable terms are on the left hand side.
\frac{2AB}{2A}=\frac{X}{2A}
Divide both sides by 2A.
B=\frac{X}{2A}
Dividing by 2A undoes the multiplication by 2A.
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