Solve V_{1}=4m^3/127^2c*22^circ=

$$V _ { 1 } = \frac { 4 m ^ { 3 } } { 127 ^ { 2 } c } \times 22 ^ { \circ } =$$

Solve for c

$$\left\{\begin{matrix}c=\frac{88m^{3}}{16129V_{1}}\text{, }&m\neq 0\text{ and }V_{1}\neq 0\\c\neq 0\text{, }&V_{1}=0\text{ and }m=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable c cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 16129c.

$$V_{1}\times 16129c=4m^{3}\times 22$$

Multiply 4 and 22 to get 88.

$$V_{1}\times 16129c=88m^{3}$$

The equation is in standard form.

$$16129V_{1}c=88m^{3}$$

Divide both sides by 16129V_{1}.

$$\frac{16129V_{1}c}{16129V_{1}}=\frac{88m^{3}}{16129V_{1}}$$

Dividing by 16129V_{1} undoes the multiplication by 16129V_{1}.

$$c=\frac{88m^{3}}{16129V_{1}}$$

Variable c cannot be equal to 0.

$$c=\frac{88m^{3}}{16129V_{1}}\text{, }c\neq 0$$

Solve for V_1

$$V_{1}=\frac{88m^{3}}{16129c}$$

$$c\neq 0$$