Solve V=frac{{A}_{8}-h}{3}

$$V = \frac{ { A }_{ 8 } -h }{ 3 }$$

Solve for A_8

$$A_{8}=3V+h$$

Steps for Solving Linear Equation

Divide each term of A_{8}-h by 3 to get \frac{1}{3}A_{8}-\frac{1}{3}h.

$$V=\frac{1}{3}A_{8}-\frac{1}{3}h$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{3}A_{8}-\frac{1}{3}h=V$$

Add \frac{1}{3}h to both sides.

$$\frac{1}{3}A_{8}=V+\frac{1}{3}h$$

The equation is in standard form.

$$\frac{1}{3}A_{8}=\frac{h}{3}+V$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}A_{8}}{\frac{1}{3}}=\frac{\frac{h}{3}+V}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$A_{8}=\frac{\frac{h}{3}+V}{\frac{1}{3}}$$

Divide V+\frac{h}{3} by \frac{1}{3} by multiplying V+\frac{h}{3} by the reciprocal of \frac{1}{3}.

$$A_{8}=3V+h$$

Solve for V

$$V=\frac{A_{8}-h}{3}$$

Solution Steps

Divide each term of A_{8}-h by 3 to get \frac{1}{3}A_{8}-\frac{1}{3}h.

$$V=\frac{1}{3}A_{8}-\frac{1}{3}h$$