Solve T^3=D(2+a)

$$T ^ { 3 } = D ( 2 + a )$$

Solve for D

$$\left\{\begin{matrix}D=\frac{T^{3}}{a+2}\text{, }&a\neq -2\\D\in \mathrm{R}\text{, }&T=0\text{ and }a=-2\end{matrix}\right.$$

Steps for Solving Linear Equation

Use the distributive property to multiply D by 2+a.

$$T^{3}=2D+Da$$

Swap sides so that all variable terms are on the left hand side.

$$2D+Da=T^{3}$$

Combine all terms containing D.

$$\left(2+a\right)D=T^{3}$$

The equation is in standard form.

$$\left(a+2\right)D=T^{3}$$

Divide both sides by 2+a.

$$\frac{\left(a+2\right)D}{a+2}=\frac{T^{3}}{a+2}$$

Dividing by 2+a undoes the multiplication by 2+a.

$$D=\frac{T^{3}}{a+2}$$

Solve for T

$$T=\sqrt[3]{D\left(a+2\right)}$$