Solve for I
I=\frac{10T-20}{53}
Solve for T
T=\frac{53I}{10}+2
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5.3I+2=T
Swap sides so that all variable terms are on the left hand side.
5.3I=T-2
Subtract 2 from both sides.
\frac{5.3I}{5.3}=\frac{T-2}{5.3}
Divide both sides of the equation by 5.3, which is the same as multiplying both sides by the reciprocal of the fraction.
I=\frac{T-2}{5.3}
Dividing by 5.3 undoes the multiplication by 5.3.
I=\frac{10T-20}{53}
Divide T-2 by 5.3 by multiplying T-2 by the reciprocal of 5.3.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
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Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}