Solve for P_3
P_{3}=-\frac{Q_{1}}{10}+20
Solve for Q_1
Q_{1}=200-10P_{3}
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200-10P_{3}=Q_{1}
Swap sides so that all variable terms are on the left hand side.
-10P_{3}=Q_{1}-200
Subtract 200 from both sides.
\frac{-10P_{3}}{-10}=\frac{Q_{1}-200}{-10}
Divide both sides by -10.
P_{3}=\frac{Q_{1}-200}{-10}
Dividing by -10 undoes the multiplication by -10.
P_{3}=-\frac{Q_{1}}{10}+20
Divide Q_{1}-200 by -10.
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