Solve P_{150}=L+[1n/100-CH/f]i

$$P _ { 150 } = L + [ \frac { \frac { 1 n } { 100 } - C H } { f } ] i$$

Solve for C

$$\left\{\begin{matrix}C=-\frac{i\left(in+100Lf-100P_{150}f\right)}{100H}\text{, }&H\neq 0\text{ and }f\neq 0\\C\in \mathrm{C}\text{, }&n=-100if\left(P_{150}-L\right)\text{ and }H=0\text{ and }f\neq 0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by f.

$$P_{150}f=fL+\left(\frac{1n}{100}-CH\right)i$$

Use the distributive property to multiply \frac{1n}{100}-CH by i.

$$P_{150}f=fL+i\times \frac{1n}{100}-iCH$$

Swap sides so that all variable terms are on the left hand side.

$$fL+i\times \frac{1n}{100}-iCH=P_{150}f$$

Subtract fL from both sides.

$$i\times \frac{1n}{100}-iCH=P_{150}f-fL$$

Subtract i\times \frac{1n}{100} from both sides.

$$-iCH=P_{150}f-fL-i\times \frac{1n}{100}$$

Multiply both sides of the equation by 100.

$$-100iCH=100\left(P_{150}f-fL\right)-i\times 1n$$

Reorder the terms.

$$-100iCH=100\left(P_{150}f-Lf\right)-in$$

Use the distributive property to multiply 100 by P_{150}f-Lf.

$$-100iCH=100P_{150}f-100Lf-in$$

The equation is in standard form.

$$\left(-100iH\right)C=-in+100P_{150}f-100Lf$$

Divide both sides by -100iH.

$$\frac{\left(-100iH\right)C}{-100iH}=\frac{-in+100P_{150}f-100Lf}{-100iH}$$

Dividing by -100iH undoes the multiplication by -100iH.

$$C=\frac{-in+100P_{150}f-100Lf}{-100iH}$$

Divide 100P_{150}f-100Lf-in by -100iH.

$$C=\frac{i\left(-in+100P_{150}f-100Lf\right)}{100H}$$

Solve for H

$$\left\{\begin{matrix}H=-\frac{i\left(in+100Lf-100P_{150}f\right)}{100C}\text{, }&C\neq 0\text{ and }f\neq 0\\H\in \mathrm{C}\text{, }&n=-100if\left(P_{150}-L\right)\text{ and }C=0\text{ and }f\neq 0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by f.

$$P_{150}f=fL+\left(\frac{1n}{100}-CH\right)i$$

Use the distributive property to multiply \frac{1n}{100}-CH by i.

$$P_{150}f=fL+i\times \frac{1n}{100}-iCH$$

Swap sides so that all variable terms are on the left hand side.

$$fL+i\times \frac{1n}{100}-iCH=P_{150}f$$

Subtract fL from both sides.

$$i\times \frac{1n}{100}-iCH=P_{150}f-fL$$

Subtract i\times \frac{1n}{100} from both sides.

$$-iCH=P_{150}f-fL-i\times \frac{1n}{100}$$

Multiply both sides of the equation by 100.

$$-100iCH=100\left(P_{150}f-fL\right)-i\times 1n$$

Reorder the terms.

$$-100iCH=100\left(P_{150}f-Lf\right)-in$$

Use the distributive property to multiply 100 by P_{150}f-Lf.

$$-100iCH=100P_{150}f-100Lf-in$$

The equation is in standard form.

$$\left(-100iC\right)H=-in+100P_{150}f-100Lf$$

Divide both sides by -100iC.

$$\frac{\left(-100iC\right)H}{-100iC}=\frac{-in+100P_{150}f-100Lf}{-100iC}$$

Dividing by -100iC undoes the multiplication by -100iC.

$$H=\frac{-in+100P_{150}f-100Lf}{-100iC}$$

Divide 100P_{150}f-100Lf-in by -100iC.

$$H=\frac{i\left(-in+100P_{150}f-100Lf\right)}{100C}$$