Solve P(x)=x^2+x^3+x^4,text{where}x=2

$$P ( x ) = x ^ { 2 } + x ^ { 3 } + x ^ { 4 } , \text { where } x = 2$$

Solve for P, x

$$x=2$$

$$P=14$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$P\times 2=2^{2}+2^{3}+2^{4}$$

Calculate 2 to the power of 2 and get 4.

$$P\times 2=4+2^{3}+2^{4}$$

Calculate 2 to the power of 3 and get 8.

$$P\times 2=4+8+2^{4}$$

Add 4 and 8 to get 12.

$$P\times 2=12+2^{4}$$

Calculate 2 to the power of 4 and get 16.

$$P\times 2=12+16$$

Add 12 and 16 to get 28.

$$P\times 2=28$$

Divide both sides by 2.

$$P=\frac{28}{2}$$

Divide 28 by 2 to get 14.

$$P=14$$

The system is now solved.

$$P=14 x=2$$