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\frac{-x^{2}+56x+240}{8}
Factor out \frac{1}{8}.
a+b=56 ab=-240=-240
Consider -x^{2}+56x+240. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx+240. To find a and b, set up a system to be solved.
-1,240 -2,120 -3,80 -4,60 -5,48 -6,40 -8,30 -10,24 -12,20 -15,16
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -240.
-1+240=239 -2+120=118 -3+80=77 -4+60=56 -5+48=43 -6+40=34 -8+30=22 -10+24=14 -12+20=8 -15+16=1
Calculate the sum for each pair.
a=60 b=-4
The solution is the pair that gives sum 56.
\left(-x^{2}+60x\right)+\left(-4x+240\right)
Rewrite -x^{2}+56x+240 as \left(-x^{2}+60x\right)+\left(-4x+240\right).
-x\left(x-60\right)-4\left(x-60\right)
Factor out -x in the first and -4 in the second group.
\left(x-60\right)\left(-x-4\right)
Factor out common term x-60 by using distributive property.
\frac{\left(x-60\right)\left(-x-4\right)}{8}
Rewrite the complete factored expression.