Solve for P
P=\frac{1}{15}\approx 0.066666667
Assign P
P≔\frac{1}{15}
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P=\frac{\frac{4!}{2!}}{\frac{6!}{\left(2!\right)^{2}}}
Multiply 2! and 2! to get \left(2!\right)^{2}.
P=\frac{4!\times \left(2!\right)^{2}}{2!\times 6!}
Divide \frac{4!}{2!} by \frac{6!}{\left(2!\right)^{2}} by multiplying \frac{4!}{2!} by the reciprocal of \frac{6!}{\left(2!\right)^{2}}.
P=\frac{2!\times 4!}{6!}
Cancel out 2! in both numerator and denominator.
P=\frac{2\times 4!}{6!}
The factorial of 2 is 2.
P=\frac{2\times 24}{6!}
The factorial of 4 is 24.
P=\frac{48}{6!}
Multiply 2 and 24 to get 48.
P=\frac{48}{720}
The factorial of 6 is 720.
P=\frac{1}{15}
Reduce the fraction \frac{48}{720} to lowest terms by extracting and canceling out 48.
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