Solve for M
M=1
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M≔1
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M=\sqrt{2}\sqrt{9}\sqrt{2}+\sqrt[3]{-125}
Factor 18=2\times 9. Rewrite the square root of the product \sqrt{2\times 9} as the product of square roots \sqrt{2}\sqrt{9}.
M=2\sqrt{9}+\sqrt[3]{-125}
Multiply \sqrt{2} and \sqrt{2} to get 2.
M=2\times 3+\sqrt[3]{-125}
Calculate the square root of 9 and get 3.
M=6+\sqrt[3]{-125}
Multiply 2 and 3 to get 6.
M=6-5
Calculate \sqrt[3]{-125} and get -5.
M=1
Subtract 5 from 6 to get 1.
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