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Solve for C_1
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Solve for L
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LC_{1}\times 2\left(r+1\right)=h-1
Multiply both sides of the equation by 2\left(h-1\right), the least common multiple of h-1,2.
2LC_{1}r+LC_{1}\times 2=h-1
Use the distributive property to multiply LC_{1}\times 2 by r+1.
\left(2Lr+L\times 2\right)C_{1}=h-1
Combine all terms containing C_{1}.
\left(2Lr+2L\right)C_{1}=h-1
The equation is in standard form.
\frac{\left(2Lr+2L\right)C_{1}}{2Lr+2L}=\frac{h-1}{2Lr+2L}
Divide both sides by 2Lr+2L.
C_{1}=\frac{h-1}{2Lr+2L}
Dividing by 2Lr+2L undoes the multiplication by 2Lr+2L.
C_{1}=\frac{h-1}{2L\left(r+1\right)}
Divide h-1 by 2Lr+2L.
LC_{1}\times 2\left(r+1\right)=h-1
Multiply both sides of the equation by 2\left(h-1\right), the least common multiple of h-1,2.
2LC_{1}r+LC_{1}\times 2=h-1
Use the distributive property to multiply LC_{1}\times 2 by r+1.
\left(2C_{1}r+C_{1}\times 2\right)L=h-1
Combine all terms containing L.
\left(2C_{1}r+2C_{1}\right)L=h-1
The equation is in standard form.
\frac{\left(2C_{1}r+2C_{1}\right)L}{2C_{1}r+2C_{1}}=\frac{h-1}{2C_{1}r+2C_{1}}
Divide both sides by 2C_{1}+2C_{1}r.
L=\frac{h-1}{2C_{1}r+2C_{1}}
Dividing by 2C_{1}+2C_{1}r undoes the multiplication by 2C_{1}+2C_{1}r.
L=\frac{h-1}{2C_{1}\left(r+1\right)}
Divide h-1 by 2C_{1}+2C_{1}r.