Solve J(k+1)*k=1050

$$J ( k + 1 ) \cdot k = 1050$$

Solve for J

$$J=\frac{1050}{k\left(k+1\right)}$$

$$k\neq -1\text{ and }k\neq 0$$

Steps for Solving Linear Equation

Use the distributive property to multiply J by k+1.

$$\left(Jk+J\right)k=1050$$

Use the distributive property to multiply Jk+J by k.

$$Jk^{2}+Jk=1050$$

Combine all terms containing J.

$$\left(k^{2}+k\right)J=1050$$

Divide both sides by k^{2}+k.

$$\frac{\left(k^{2}+k\right)J}{k^{2}+k}=\frac{1050}{k^{2}+k}$$

Dividing by k^{2}+k undoes the multiplication by k^{2}+k.

$$J=\frac{1050}{k^{2}+k}$$

Divide 1050 by k^{2}+k.

$$J=\frac{1050}{k\left(k+1\right)}$$

Solve for k

$$k=\frac{\sqrt{J^{2}+4200J}}{2J}-\frac{1}{2}$$

$$k=-\frac{\sqrt{J^{2}+4200J}}{2J}-\frac{1}{2}\text{, }J>0\text{ or }J\leq -4200$$