Solve for J
J=10\sqrt{7}+32\approx 58.457513111
Assign J
J≔10\sqrt{7}+32
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J=25+10\sqrt{7}+\left(\sqrt{7}\right)^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(5+\sqrt{7}\right)^{2}.
J=25+10\sqrt{7}+7
The square of \sqrt{7} is 7.
J=32+10\sqrt{7}
Add 25 and 7 to get 32.
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