Solve J=(1/8-7/12)div(7/6+7/16)

$$J = ( \frac { 1 } { 8 } - \frac { 7 } { 12 } ) \div ( \frac { 7 } { 6 } + \frac { 7 } { 16 } )$$

Solve for J

$$J=-\frac{2}{7}\approx -0.285714286$$

Steps for Solving Linear Equation

Least common multiple of 8 and 12 is 24. Convert \frac{1}{8} and \frac{7}{12} to fractions with denominator 24.

$$J=\frac{\frac{3}{24}-\frac{14}{24}}{\frac{7}{6}+\frac{7}{16}}$$

Since \frac{3}{24} and \frac{14}{24} have the same denominator, subtract them by subtracting their numerators.

$$J=\frac{\frac{3-14}{24}}{\frac{7}{6}+\frac{7}{16}}$$

Subtract 14 from 3 to get -11.

$$J=\frac{-\frac{11}{24}}{\frac{7}{6}+\frac{7}{16}}$$

Least common multiple of 6 and 16 is 48. Convert \frac{7}{6} and \frac{7}{16} to fractions with denominator 48.

$$J=\frac{-\frac{11}{24}}{\frac{56}{48}+\frac{21}{48}}$$

Since \frac{56}{48} and \frac{21}{48} have the same denominator, add them by adding their numerators.

$$J=\frac{-\frac{11}{24}}{\frac{56+21}{48}}$$

Add 56 and 21 to get 77.

$$J=\frac{-\frac{11}{24}}{\frac{77}{48}}$$

Divide -\frac{11}{24} by \frac{77}{48} by multiplying -\frac{11}{24} by the reciprocal of \frac{77}{48}.

$$J=-\frac{11}{24}\times \frac{48}{77}$$

Multiply -\frac{11}{24} times \frac{48}{77} by multiplying numerator times numerator and denominator times denominator.

$$J=\frac{-11\times 48}{24\times 77}$$

Do the multiplications in the fraction \frac{-11\times 48}{24\times 77}.

$$J=\frac{-528}{1848}$$

Reduce the fraction \frac{-528}{1848} to lowest terms by extracting and canceling out 264.

$$J=-\frac{2}{7}$$

Assign J

$$J≔-\frac{2}{7}$$