Solve Ix+2/5I=12

$$I x + 2 / 5 I = 12$$

Solve for I

$$I=\frac{60}{5x+2}$$

$$x\neq -\frac{2}{5}$$

Steps for Solving Linear Equation

Combine all terms containing I.

$$\left(x+\frac{2}{5}\right)I=12$$

Divide both sides by x+\frac{2}{5}.

$$\frac{\left(x+\frac{2}{5}\right)I}{x+\frac{2}{5}}=\frac{12}{x+\frac{2}{5}}$$

Dividing by x+\frac{2}{5} undoes the multiplication by x+\frac{2}{5}.

$$I=\frac{12}{x+\frac{2}{5}}$$

Divide 12 by x+\frac{2}{5}.

$$I=\frac{60}{5x+2}$$

Solve for x

$$x=-\frac{2}{5}+\frac{12}{I}$$

$$I\neq 0$$

Steps for Solving Linear Equation

Subtract \frac{2}{5}I from both sides.

$$Ix=12-\frac{2}{5}I$$

The equation is in standard form.

$$Ix=-\frac{2I}{5}+12$$

Divide both sides by I.

$$\frac{Ix}{I}=\frac{-\frac{2I}{5}+12}{I}$$

Dividing by I undoes the multiplication by I.

$$x=\frac{-\frac{2I}{5}+12}{I}$$

Divide 12-\frac{2I}{5} by I.

$$x=-\frac{2}{5}+\frac{12}{I}$$