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\left(2xy+\frac{x^{2}}{2}+С\right)I=26
The equation is in standard form.
\frac{\left(2xy+\frac{x^{2}}{2}+С\right)I}{2xy+\frac{x^{2}}{2}+С}=\frac{26}{2xy+\frac{x^{2}}{2}+С}
Divide both sides by \frac{1}{2}x^{2}+2yx+С.
I=\frac{26}{2xy+\frac{x^{2}}{2}+С}
Dividing by \frac{1}{2}x^{2}+2yx+С undoes the multiplication by \frac{1}{2}x^{2}+2yx+С.