Solve I=mgsqrt{1+(1/n)^2}

$$I = m g \sqrt { 1 + ( \frac { 1 } { n } ) ^ { 2 } }$$

Solve for g

$$\left\{\begin{matrix}g=\frac{I|n|}{m\sqrt{n^{2}+1}}\text{, }&m\neq 0\text{ and }n\neq 0\\g\in \mathrm{R}\text{, }&I=0\text{ and }m=0\text{ and }n\neq 0\end{matrix}\right.$$

Steps for Solving Linear Equation

To raise \frac{1}{n} to a power, raise both numerator and denominator to the power and then divide.

$$I=mg\sqrt{1+\frac{1^{2}}{n^{2}}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{n^{2}}{n^{2}}.

$$I=mg\sqrt{\frac{n^{2}}{n^{2}}+\frac{1^{2}}{n^{2}}}$$

Since \frac{n^{2}}{n^{2}} and \frac{1^{2}}{n^{2}} have the same denominator, add them by adding their numerators.

$$I=mg\sqrt{\frac{n^{2}+1^{2}}{n^{2}}}$$

Combine like terms in n^{2}+1^{2}.

$$I=mg\sqrt{\frac{n^{2}+1}{n^{2}}}$$

Swap sides so that all variable terms are on the left hand side.

$$mg\sqrt{\frac{n^{2}+1}{n^{2}}}=I$$

The equation is in standard form.

$$\sqrt{\frac{n^{2}+1}{n^{2}}}mg=I$$

Divide both sides by m\sqrt{\left(n^{2}+1\right)n^{-2}}.

$$\frac{\sqrt{\frac{n^{2}+1}{n^{2}}}mg}{\sqrt{\frac{n^{2}+1}{n^{2}}}m}=\frac{I}{\sqrt{\frac{n^{2}+1}{n^{2}}}m}$$

Dividing by m\sqrt{\left(n^{2}+1\right)n^{-2}} undoes the multiplication by m\sqrt{\left(n^{2}+1\right)n^{-2}}.

$$g=\frac{I}{\sqrt{\frac{n^{2}+1}{n^{2}}}m}$$

Divide I by m\sqrt{\left(n^{2}+1\right)n^{-2}}.

$$g=\frac{I|n|}{m\sqrt{n^{2}+1}}$$

Solve for I

$$I=\frac{gm\sqrt{n^{2}+1}}{|n|}$$

$$n\neq 0$$