Solve Halpha=2kpi+pi/2(kinZ)

$$H \alpha = 2 k \pi + \frac { \pi } { 2 } ( k \in Z )$$

Solve for H

$$\left\{\begin{matrix}H=\frac{\pi \left(\left(k\in Z\right)+4k\right)}{2\alpha }\text{, }&\alpha \neq 0\\H\in \mathrm{R}\text{, }&\pi \left(\left(k\in Z\right)+4k\right)=0\text{ and }\alpha =0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$2H\alpha =4k\pi +\pi \left(k\in Z\right)$$

The equation is in standard form.

$$2\alpha H=\pi \left(k\in Z\right)+4\pi k$$

Divide both sides by 2\alpha .

$$\frac{2\alpha H}{2\alpha }=\frac{\pi \left(\left(k\in Z\right)+4k\right)}{2\alpha }$$

Dividing by 2\alpha undoes the multiplication by 2\alpha .

$$H=\frac{\pi \left(\left(k\in Z\right)+4k\right)}{2\alpha }$$