Solve F(x)-2=x^3-7/2x^2-41/4x+103/25

$$F(x)-2 = { x }^{ 3 } - \frac{ 7 }{ 2 } { x }^{ 2 } - \frac{ 41 }{ 4 } x+ \frac{ 103 }{ 25 }$$

Solve for F

$$F=x^{2}-\frac{7x}{2}-\frac{41}{4}+\frac{153}{25x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Add 2 to both sides.

$$Fx=x^{3}-\frac{7}{2}x^{2}-\frac{41}{4}x+\frac{103}{25}+2$$

Add \frac{103}{25} and 2 to get \frac{153}{25}.

$$Fx=x^{3}-\frac{7}{2}x^{2}-\frac{41}{4}x+\frac{153}{25}$$

The equation is in standard form.

$$xF=x^{3}-\frac{7x^{2}}{2}-\frac{41x}{4}+\frac{153}{25}$$

Divide both sides by x.

$$\frac{xF}{x}=\frac{x^{3}-\frac{7x^{2}}{2}-\frac{41x}{4}+\frac{153}{25}}{x}$$

Dividing by x undoes the multiplication by x.

$$F=\frac{x^{3}-\frac{7x^{2}}{2}-\frac{41x}{4}+\frac{153}{25}}{x}$$

Divide x^{3}-\frac{7x^{2}}{2}-\frac{41x}{4}+\frac{153}{25} by x.

$$F=x^{2}-\frac{7x}{2}-\frac{41}{4}+\frac{153}{25x}$$