F ( x ) = 3 x - x ^ { 2 } \quad ( - 2,7 )
Solve for F
\left\{\begin{matrix}\\F=\frac{27x}{10}+3\text{, }&\text{unconditionally}\\F\in \mathrm{R}\text{, }&x=0\end{matrix}\right.
Solve for x
x=\frac{10\left(F-3\right)}{27}
x=0
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Fx=3x+2,7x^{2}
Multiply -1 and -2,7 to get 2,7.
xF=\frac{27x^{2}}{10}+3x
The equation is in standard form.
\frac{xF}{x}=\frac{x\left(\frac{27x}{10}+3\right)}{x}
Divide both sides by x.
F=\frac{x\left(\frac{27x}{10}+3\right)}{x}
Dividing by x undoes the multiplication by x.
F=\frac{27x}{10}+3
Divide x\left(3+\frac{27x}{10}\right) by x.
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