Solve F(x)=-8xquad[1,3]

$$F ( x ) = - 8 x \quad [ 1,3 ]$$

Solve for F

$$\left\{\begin{matrix}\\F=-10,4\text{, }&\text{unconditionally}\\F\in \mathrm{R}\text{, }&x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply -8 and 1,3 to get -10,4.

$$Fx=-10,4x$$

The equation is in standard form.

$$xF=-\frac{52x}{5}$$

Divide both sides by x.

$$\frac{xF}{x}=-\frac{\frac{52x}{5}}{x}$$

Dividing by x undoes the multiplication by x.

$$F=-\frac{\frac{52x}{5}}{x}$$

Divide -\frac{52x}{5} by x.

$$F=-\frac{52}{5}$$

Solve for x

$$\left\{\begin{matrix}\\x=0\text{, }&\text{unconditionally}\\x\in \mathrm{R}\text{, }&F=-\frac{52}{5}\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply -8 and 1,3 to get -10,4.

$$Fx=-10,4x$$

Add 10,4x to both sides.

$$Fx+10,4x=0$$

Combine all terms containing x.

$$\left(F+10,4\right)x=0$$

Divide 0 by 10,4+F.

$$x=0$$