Solve F(1/4)=-2(1/4)^3+3

$$F ( 1 / 4 ) = - 2 ( 1 / 4 ) ^ { 3 } + 3$$

Evaluate

$$\frac{95}{32}=2.96875$$

Solution Steps

Calculate \frac{1}{4} to the power of 3 and get \frac{1}{64}.

$$-2\times \frac{1}{64}+3$$

Multiply -2 and \frac{1}{64} to get \frac{-2}{64}.

$$\frac{-2}{64}+3$$

Reduce the fraction \frac{-2}{64} to lowest terms by extracting and canceling out 2.

$$-\frac{1}{32}+3$$

Convert 3 to fraction \frac{96}{32}.

$$-\frac{1}{32}+\frac{96}{32}$$

Since -\frac{1}{32} and \frac{96}{32} have the same denominator, add them by adding their numerators.

$$\frac{-1+96}{32}$$

Add -1 and 96 to get 95.

$$\frac{95}{32}$$

Factor

$$\frac{5 \cdot 19}{2 ^ {5}} = 2\frac{31}{32} = 2.96875$$