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Solve for A (complex solution)
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Solve for A
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Solve for B (complex solution)
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Solve for B
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BC+\frac{\mathrm{d}}{\mathrm{d}x}(B)\frac{\mathrm{d}}{\mathrm{d}x}(C)+A\frac{\mathrm{d}}{\mathrm{d}x}(B)C=F
Swap sides so that all variable terms are on the left hand side.
\frac{\mathrm{d}}{\mathrm{d}x}(B)\frac{\mathrm{d}}{\mathrm{d}x}(C)+A\frac{\mathrm{d}}{\mathrm{d}x}(B)C=F-BC
Subtract BC from both sides.
A\frac{\mathrm{d}}{\mathrm{d}x}(B)C=F-BC-\frac{\mathrm{d}}{\mathrm{d}x}(B)\frac{\mathrm{d}}{\mathrm{d}x}(C)
Subtract \frac{\mathrm{d}}{\mathrm{d}x}(B)\frac{\mathrm{d}}{\mathrm{d}x}(C) from both sides.
AC\frac{\mathrm{d}}{\mathrm{d}x}(B)=-\frac{\mathrm{d}}{\mathrm{d}x}(B)\frac{\mathrm{d}}{\mathrm{d}x}(C)-BC+F
Reorder the terms.
0=F-BC
The equation is in standard form.
A\in
This is false for any A.
BC+\frac{\mathrm{d}}{\mathrm{d}x}(B)\frac{\mathrm{d}}{\mathrm{d}x}(C)+A\frac{\mathrm{d}}{\mathrm{d}x}(B)C=F
Swap sides so that all variable terms are on the left hand side.
\frac{\mathrm{d}}{\mathrm{d}x}(B)\frac{\mathrm{d}}{\mathrm{d}x}(C)+A\frac{\mathrm{d}}{\mathrm{d}x}(B)C=F-BC
Subtract BC from both sides.
A\frac{\mathrm{d}}{\mathrm{d}x}(B)C=F-BC-\frac{\mathrm{d}}{\mathrm{d}x}(B)\frac{\mathrm{d}}{\mathrm{d}x}(C)
Subtract \frac{\mathrm{d}}{\mathrm{d}x}(B)\frac{\mathrm{d}}{\mathrm{d}x}(C) from both sides.
AC\frac{\mathrm{d}}{\mathrm{d}x}(B)=-\frac{\mathrm{d}}{\mathrm{d}x}(B)\frac{\mathrm{d}}{\mathrm{d}x}(C)-BC+F
Reorder the terms.
0=F-BC
The equation is in standard form.
A\in
This is false for any A.