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Solve for E (complex solution)
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Solve for b (complex solution)
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Solve for E
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Solve for b
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Ex+2-\left(bx-b\right)=5x-3
Use the distributive property to multiply b by x-1.
Ex+2-bx+b=5x-3
To find the opposite of bx-b, find the opposite of each term.
Ex-bx+b=5x-3-2
Subtract 2 from both sides.
Ex-bx+b=5x-5
Subtract 2 from -3 to get -5.
Ex+b=5x-5+bx
Add bx to both sides.
Ex=5x-5+bx-b
Subtract b from both sides.
xE=bx+5x-b-5
The equation is in standard form.
\frac{xE}{x}=\frac{\left(x-1\right)\left(b+5\right)}{x}
Divide both sides by x.
E=\frac{\left(x-1\right)\left(b+5\right)}{x}
Dividing by x undoes the multiplication by x.
Ex+2-\left(bx-b\right)=5x-3
Use the distributive property to multiply b by x-1.
Ex+2-bx+b=5x-3
To find the opposite of bx-b, find the opposite of each term.
2-bx+b=5x-3-Ex
Subtract Ex from both sides.
-bx+b=5x-3-Ex-2
Subtract 2 from both sides.
-bx+b=5x-5-Ex
Subtract 2 from -3 to get -5.
\left(-x+1\right)b=5x-5-Ex
Combine all terms containing b.
\left(1-x\right)b=-Ex+5x-5
The equation is in standard form.
\frac{\left(1-x\right)b}{1-x}=\frac{-Ex+5x-5}{1-x}
Divide both sides by -x+1.
b=\frac{-Ex+5x-5}{1-x}
Dividing by -x+1 undoes the multiplication by -x+1.
Ex+2-\left(bx-b\right)=5x-3
Use the distributive property to multiply b by x-1.
Ex+2-bx+b=5x-3
To find the opposite of bx-b, find the opposite of each term.
Ex-bx+b=5x-3-2
Subtract 2 from both sides.
Ex-bx+b=5x-5
Subtract 2 from -3 to get -5.
Ex+b=5x-5+bx
Add bx to both sides.
Ex=5x-5+bx-b
Subtract b from both sides.
xE=bx+5x-b-5
The equation is in standard form.
\frac{xE}{x}=\frac{\left(x-1\right)\left(b+5\right)}{x}
Divide both sides by x.
E=\frac{\left(x-1\right)\left(b+5\right)}{x}
Dividing by x undoes the multiplication by x.
Ex+2-\left(bx-b\right)=5x-3
Use the distributive property to multiply b by x-1.
Ex+2-bx+b=5x-3
To find the opposite of bx-b, find the opposite of each term.
2-bx+b=5x-3-Ex
Subtract Ex from both sides.
-bx+b=5x-3-Ex-2
Subtract 2 from both sides.
-bx+b=5x-5-Ex
Subtract 2 from -3 to get -5.
\left(-x+1\right)b=5x-5-Ex
Combine all terms containing b.
\left(1-x\right)b=-Ex+5x-5
The equation is in standard form.
\frac{\left(1-x\right)b}{1-x}=\frac{-Ex+5x-5}{1-x}
Divide both sides by 1-x.
b=\frac{-Ex+5x-5}{1-x}
Dividing by 1-x undoes the multiplication by 1-x.