Solve E-104+22.36-225:25-15.5+5=

$$E - 104 + 22.36 - 225 : 25 - 15.5 + 5 =$$

Evaluate

$$E-101.14$$

Solution Steps

Add -104 and 22.36 to get -81.64.

$$E-81.64-\frac{225}{25}-15.5+5$$

Divide 225 by 25 to get 9.

$$E-81.64-9-15.5+5$$

Subtract 9 from -81.64 to get -90.64.

$$E-90.64-15.5+5$$

Subtract 15.5 from -90.64 to get -106.14.

$$E-106.14+5$$

Add -106.14 and 5 to get -101.14.

$$E-101.14$$

Differentiate w.r.t. E

$$1$$

Steps Using Derivative Rule for Sum

Add -104 and 22.36 to get -81.64.

$$\frac{\mathrm{d}}{\mathrm{d}E}(E-81.64-\frac{225}{25}-15.5+5)$$

Divide 225 by 25 to get 9.

$$\frac{\mathrm{d}}{\mathrm{d}E}(E-81.64-9-15.5+5)$$

Subtract 9 from -81.64 to get -90.64.

$$\frac{\mathrm{d}}{\mathrm{d}E}(E-90.64-15.5+5)$$

Subtract 15.5 from -90.64 to get -106.14.

$$\frac{\mathrm{d}}{\mathrm{d}E}(E-106.14+5)$$

Add -106.14 and 5 to get -101.14.

$$\frac{\mathrm{d}}{\mathrm{d}E}(E-101.14)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$E^{1-1}$$

Subtract 1 from 1.

$$E^{0}$$

For any term t except 0, t^{0}=1.

$$1$$