Solve E*(11-3)^2:4+sqrt{10^2-6^2-28:2^2*3+sqrt{121}}=

$$E \cdot ( 11 - 3 ) ^ { 2 } : 4 + \sqrt { 10 ^ { 2 } - 6 ^ { 2 } - 28 : 2 ^ { 2 } \cdot 3 + \sqrt { 121 } } =$$

Evaluate

$$16E+3\sqrt{6}$$

Solution Steps

Subtract 3 from 11 to get 8.

$$\frac{E\times 8^{2}}{4}+\sqrt{10^{2}-6^{2}-\frac{28}{2^{2}}\times 3+\sqrt{121}}$$

Calculate 8 to the power of 2 and get 64.

$$\frac{E\times 64}{4}+\sqrt{10^{2}-6^{2}-\frac{28}{2^{2}}\times 3+\sqrt{121}}$$

Divide E\times 64 by 4 to get E\times 16.

$$E\times 16+\sqrt{10^{2}-6^{2}-\frac{28}{2^{2}}\times 3+\sqrt{121}}$$

Calculate 10 to the power of 2 and get 100.

$$E\times 16+\sqrt{100-6^{2}-\frac{28}{2^{2}}\times 3+\sqrt{121}}$$

Calculate 6 to the power of 2 and get 36.

$$E\times 16+\sqrt{100-36-\frac{28}{2^{2}}\times 3+\sqrt{121}}$$

Subtract 36 from 100 to get 64.

$$E\times 16+\sqrt{64-\frac{28}{2^{2}}\times 3+\sqrt{121}}$$

Calculate 2 to the power of 2 and get 4.

$$E\times 16+\sqrt{64-\frac{28}{4}\times 3+\sqrt{121}}$$

Divide 28 by 4 to get 7.

$$E\times 16+\sqrt{64-7\times 3+\sqrt{121}}$$

Multiply 7 and 3 to get 21.

$$E\times 16+\sqrt{64-21+\sqrt{121}}$$

Subtract 21 from 64 to get 43.

$$E\times 16+\sqrt{43+\sqrt{121}}$$

Calculate the square root of 121 and get 11.

$$E\times 16+\sqrt{43+11}$$

Add 43 and 11 to get 54.

$$E\times 16+\sqrt{54}$$

Factor 54=3^{2}\times 6. Rewrite the square root of the product \sqrt{3^{2}\times 6} as the product of square roots \sqrt{3^{2}}\sqrt{6}. Take the square root of 3^{2}.

$$E\times 16+3\sqrt{6}$$

Factor

$$16E+3\sqrt{6}$$