Solve for D
D=6\sqrt{15}\approx 23.237900077
Assign D
D≔6\sqrt{15}
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D=\sqrt{540}
Multiply 18 and 30 to get 540.
D=6\sqrt{15}
Factor 540=6^{2}\times 15. Rewrite the square root of the product \sqrt{6^{2}\times 15} as the product of square roots \sqrt{6^{2}}\sqrt{15}. Take the square root of 6^{2}.
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