Solve D=j+p/2

$$D = \frac { j + p } { 2 }$$

Solve for j

$$j=2D-p$$

Steps for Solving Linear Equation

Divide each term of j+p by 2 to get \frac{1}{2}j+\frac{1}{2}p.

$$D=\frac{1}{2}j+\frac{1}{2}p$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}j+\frac{1}{2}p=D$$

Subtract \frac{1}{2}p from both sides.

$$\frac{1}{2}j=D-\frac{1}{2}p$$

The equation is in standard form.

$$\frac{1}{2}j=-\frac{p}{2}+D$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}j}{\frac{1}{2}}=\frac{-\frac{p}{2}+D}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$j=\frac{-\frac{p}{2}+D}{\frac{1}{2}}$$

Divide D-\frac{p}{2} by \frac{1}{2} by multiplying D-\frac{p}{2} by the reciprocal of \frac{1}{2}.

$$j=2D-p$$

Solve for D

$$D=\frac{p+j}{2}$$

Solution Steps

Divide each term of j+p by 2 to get \frac{1}{2}j+\frac{1}{2}p.

$$D=\frac{1}{2}j+\frac{1}{2}p$$