Solve D=[3^24*(-3)^12:(-3)^2]:(-9)^12

$$D = [ 3 ^ { 24 } \cdot ( - 3 ) ^ { 12 } : ( - 3 ) ^ { 2 } ] : ( - 9 ) ^ { 12 }$$

Solve for D

$$D=59049$$

Steps for Solving Linear Equation

Cancel out \left(-3\right)^{2} in both numerator and denominator.

$$D=\frac{\left(-3\right)^{10}\times 3^{24}}{\left(-9\right)^{12}}$$

Calculate -9 to the power of 12 and get 282429536481.

$$D=\frac{\left(-3\right)^{10}\times 3^{24}}{282429536481}$$

Calculate -3 to the power of 10 and get 59049.

$$D=\frac{59049\times 3^{24}}{282429536481}$$

Calculate 3 to the power of 24 and get 282429536481.

$$D=\frac{59049\times 282429536481}{282429536481}$$

Multiply 59049 and 282429536481 to get 16677181699666569.

$$D=\frac{16677181699666569}{282429536481}$$

Divide 16677181699666569 by 282429536481 to get 59049.

$$D=59049$$

Assign D

$$D≔59049$$