Solve for C
C=n-3+\frac{2}{n}
n\neq 0
Solve for n (complex solution)
n=\frac{-\sqrt{C^{2}+6C+1}+C+3}{2}
n=\frac{\sqrt{C^{2}+6C+1}+C+3}{2}
Solve for n
n=\frac{-\sqrt{C^{2}+6C+1}+C+3}{2}
n=\frac{\sqrt{C^{2}+6C+1}+C+3}{2}\text{, }C\geq 2\sqrt{2}-3\text{ or }C\leq -2\sqrt{2}-3
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Cn=n^{2}-3n+2
Use the distributive property to multiply n-1 by n-2 and combine like terms.
nC=n^{2}-3n+2
The equation is in standard form.
\frac{nC}{n}=\frac{\left(n-2\right)\left(n-1\right)}{n}
Divide both sides by n.
C=\frac{\left(n-2\right)\left(n-1\right)}{n}
Dividing by n undoes the multiplication by n.
C=n-3+\frac{2}{n}
Divide \left(-2+n\right)\left(-1+n\right) by n.
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