Solve CB=sqrt{T^2+7^2}

$$C B = \sqrt { T ^ { 2 } + 7 ^ { 2 } }$$

Solve for B (complex solution)

$$\left\{\begin{matrix}B=\frac{\sqrt{T^{2}+49}}{C}\text{, }&C\neq 0\\B\in \mathrm{C}\text{, }&\left(T=7i\text{ or }T=-7i\right)\text{ and }C=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Calculate 7 to the power of 2 and get 49.

$$CB=\sqrt{T^{2}+49}$$

Divide both sides by C.

$$\frac{CB}{C}=\frac{\sqrt{T^{2}+49}}{C}$$

Dividing by C undoes the multiplication by C.

$$B=\frac{\sqrt{T^{2}+49}}{C}$$

Solve for C (complex solution)

$$\left\{\begin{matrix}C=\frac{\sqrt{T^{2}+49}}{B}\text{, }&B\neq 0\\C\in \mathrm{C}\text{, }&\left(T=7i\text{ or }T=-7i\right)\text{ and }B=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Calculate 7 to the power of 2 and get 49.

$$CB=\sqrt{T^{2}+49}$$

The equation is in standard form.

$$BC=\sqrt{T^{2}+49}$$

Divide both sides by B.

$$\frac{BC}{B}=\frac{\sqrt{T^{2}+49}}{B}$$

Dividing by B undoes the multiplication by B.

$$C=\frac{\sqrt{T^{2}+49}}{B}$$

Solve for B

$$B=\frac{\sqrt{T^{2}+49}}{C}$$

$$C\neq 0$$

Steps for Solving Linear Equation

Calculate 7 to the power of 2 and get 49.

$$CB=\sqrt{T^{2}+49}$$

Divide both sides by C.

$$\frac{CB}{C}=\frac{\sqrt{T^{2}+49}}{C}$$

Dividing by C undoes the multiplication by C.

$$B=\frac{\sqrt{T^{2}+49}}{C}$$

Solve for C

$$C=\frac{\sqrt{T^{2}+49}}{B}$$

$$B\neq 0$$

Steps for Solving Linear Equation

Calculate 7 to the power of 2 and get 49.

$$CB=\sqrt{T^{2}+49}$$

The equation is in standard form.

$$BC=\sqrt{T^{2}+49}$$

Divide both sides by B.

$$\frac{BC}{B}=\frac{\sqrt{T^{2}+49}}{B}$$

Dividing by B undoes the multiplication by B.

$$C=\frac{\sqrt{T^{2}+49}}{B}$$