Solve C(520)=150+520/7+34,000/520

$$C ( 520 ) = 150 + \frac { 520 } { 7 } + \frac { 34,000 } { 520 }$$

Evaluate

$$\frac{26360}{91}\approx 289.67032967$$

Solution Steps

Convert 150 to fraction \frac{1050}{7}.

$$\frac{1050}{7}+\frac{520}{7}+\frac{34000}{520}$$

Since \frac{1050}{7} and \frac{520}{7} have the same denominator, add them by adding their numerators.

$$\frac{1050+520}{7}+\frac{34000}{520}$$

Add 1050 and 520 to get 1570.

$$\frac{1570}{7}+\frac{34000}{520}$$

Reduce the fraction \frac{34000}{520} to lowest terms by extracting and canceling out 40.

$$\frac{1570}{7}+\frac{850}{13}$$

Least common multiple of 7 and 13 is 91. Convert \frac{1570}{7} and \frac{850}{13} to fractions with denominator 91.

$$\frac{20410}{91}+\frac{5950}{91}$$

Since \frac{20410}{91} and \frac{5950}{91} have the same denominator, add them by adding their numerators.

$$\frac{20410+5950}{91}$$

Add 20410 and 5950 to get 26360.

$$\frac{26360}{91}$$

Factor

$$\frac{2 ^ {3} \cdot 5 \cdot 659}{7 \cdot 13} = 289\frac{61}{91} = 289.6703296703297$$