Solve for C
C=z^{2}-\frac{1}{25}
Solve for z
z=\frac{\sqrt{25C+1}}{5}
z=-\frac{\sqrt{25C+1}}{5}\text{, }C\geq -\frac{1}{25}
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C=z^{2}-\frac{1}{25}
Consider \left(z+\frac{1}{5}\right)\left(z-\frac{1}{5}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square \frac{1}{5}.
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