Solve for F
F=\frac{9C}{5}+3
Solve for C
C=\frac{5\left(F-3\right)}{9}
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C=\frac{5}{9}F-\frac{5}{3}
Use the distributive property to multiply \frac{5}{9} by F-3.
\frac{5}{9}F-\frac{5}{3}=C
Swap sides so that all variable terms are on the left hand side.
\frac{5}{9}F=C+\frac{5}{3}
Add \frac{5}{3} to both sides.
\frac{\frac{5}{9}F}{\frac{5}{9}}=\frac{C+\frac{5}{3}}{\frac{5}{9}}
Divide both sides of the equation by \frac{5}{9}, which is the same as multiplying both sides by the reciprocal of the fraction.
F=\frac{C+\frac{5}{3}}{\frac{5}{9}}
Dividing by \frac{5}{9} undoes the multiplication by \frac{5}{9}.
F=\frac{9C}{5}+3
Divide C+\frac{5}{3} by \frac{5}{9} by multiplying C+\frac{5}{3} by the reciprocal of \frac{5}{9}.
C=\frac{5}{9}F-\frac{5}{3}
Use the distributive property to multiply \frac{5}{9} by F-3.
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