Solve C=[2*(-2)^12:(-2)^15]:(-2)^2

$$C = [ 2 \cdot ( - 2 ) ^ { 12 } : ( - 2 ) ^ { 15 } ] : ( - 2 ) ^ { 2 }$$

Solve for C

$$C=-\frac{1}{16}=-0.0625$$

Steps for Solving Linear Equation

Cancel out \left(-2\right)^{12} in both numerator and denominator.

$$C=\frac{\frac{2}{\left(-2\right)^{3}}}{\left(-2\right)^{2}}$$

Calculate -2 to the power of 3 and get -8.

$$C=\frac{\frac{2}{-8}}{\left(-2\right)^{2}}$$

Reduce the fraction \frac{2}{-8} to lowest terms by extracting and canceling out 2.

$$C=\frac{-\frac{1}{4}}{\left(-2\right)^{2}}$$

Calculate -2 to the power of 2 and get 4.

$$C=\frac{-\frac{1}{4}}{4}$$

Express \frac{-\frac{1}{4}}{4} as a single fraction.

$$C=\frac{-1}{4\times 4}$$

Multiply 4 and 4 to get 16.

$$C=\frac{-1}{16}$$

Fraction \frac{-1}{16} can be rewritten as -\frac{1}{16} by extracting the negative sign.

$$C=-\frac{1}{16}$$

Assign C

$$C≔-\frac{1}{16}$$