Solve C=[2^7*(-2)^12:(-2)^15]:(-2)^2

$$C = [ 2 ^ { 7 } \cdot ( - 2 ) ^ { 12 } : ( - 2 ) ^ { 15 } ] : ( - 2 ) ^ { 2 }$$

Solve for C

$$C=-4$$

Steps for Solving Linear Equation

Cancel out \left(-2\right)^{12} in both numerator and denominator.

$$C=\frac{\frac{2^{7}}{\left(-2\right)^{3}}}{\left(-2\right)^{2}}$$

Calculate 2 to the power of 7 and get 128.

$$C=\frac{\frac{128}{\left(-2\right)^{3}}}{\left(-2\right)^{2}}$$

Calculate -2 to the power of 3 and get -8.

$$C=\frac{\frac{128}{-8}}{\left(-2\right)^{2}}$$

Divide 128 by -8 to get -16.

$$C=\frac{-16}{\left(-2\right)^{2}}$$

Calculate -2 to the power of 2 and get 4.

$$C=\frac{-16}{4}$$

Divide -16 by 4 to get -4.

$$C=-4$$

Assign C

$$C≔-4$$