Solve BC=sqrt{left(10-11right)^2+left(0-11right)^2}

$$BC = \sqrt{ { \left(10-11 \right) }^{ 2 } + { \left(0-11 \right) }^{ 2 } }$$

Solve for B

$$B=\frac{\sqrt{122}}{C}$$

$$C\neq 0$$

Steps for Solving Linear Equation

Subtract 11 from 10 to get -1.

$$BC=\sqrt{\left(-1\right)^{2}+\left(0-11\right)^{2}}$$

Calculate -1 to the power of 2 and get 1.

$$BC=\sqrt{1+\left(0-11\right)^{2}}$$

Subtract 11 from 0 to get -11.

$$BC=\sqrt{1+\left(-11\right)^{2}}$$

Calculate -11 to the power of 2 and get 121.

$$BC=\sqrt{1+121}$$

Add 1 and 121 to get 122.

$$BC=\sqrt{122}$$

The equation is in standard form.

$$CB=\sqrt{122}$$

Divide both sides by C.

$$\frac{CB}{C}=\frac{\sqrt{122}}{C}$$

Dividing by C undoes the multiplication by C.

$$B=\frac{\sqrt{122}}{C}$$

Solve for C

$$C=\frac{\sqrt{122}}{B}$$

$$B\neq 0$$

Steps for Solving Linear Equation

Subtract 11 from 10 to get -1.

$$BC=\sqrt{\left(-1\right)^{2}+\left(0-11\right)^{2}}$$

Calculate -1 to the power of 2 and get 1.

$$BC=\sqrt{1+\left(0-11\right)^{2}}$$

Subtract 11 from 0 to get -11.

$$BC=\sqrt{1+\left(-11\right)^{2}}$$

Calculate -11 to the power of 2 and get 121.

$$BC=\sqrt{1+121}$$

Add 1 and 121 to get 122.

$$BC=\sqrt{122}$$

Divide both sides by B.

$$\frac{BC}{B}=\frac{\sqrt{122}}{B}$$

Dividing by B undoes the multiplication by B.

$$C=\frac{\sqrt{122}}{B}$$