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Solve for B
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BS=\frac{0,0016-0,08x+x^{2}}{\left(0,05-x\right)^{2}}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(0,04-x\right)^{2}.
BS=\frac{0,0016-0,08x+x^{2}}{0,0025-0,1x+x^{2}}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(0,05-x\right)^{2}.
SB=\frac{x^{2}-\frac{2x}{25}+0,0016}{x^{2}-\frac{x}{10}+0,0025}
The equation is in standard form.
\frac{SB}{S}=\frac{16\left(25x-1\right)^{2}}{25\left(20x-1\right)^{2}S}
Divide both sides by S.
B=\frac{16\left(25x-1\right)^{2}}{25\left(20x-1\right)^{2}S}
Dividing by S undoes the multiplication by S.
B=\frac{16\left(25x-1\right)^{2}}{25S\left(20x-1\right)^{2}}
Divide \frac{16\left(25x-1\right)^{2}}{25\left(20x-1\right)^{2}} by S.
BS=\frac{0,0016-0,08x+x^{2}}{\left(0,05-x\right)^{2}}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(0,04-x\right)^{2}.
BS=\frac{0,0016-0,08x+x^{2}}{0,0025-0,1x+x^{2}}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(0,05-x\right)^{2}.
BS=\frac{x^{2}-\frac{2x}{25}+0,0016}{x^{2}-\frac{x}{10}+0,0025}
The equation is in standard form.
\frac{BS}{B}=\frac{16\left(25x-1\right)^{2}}{25\left(20x-1\right)^{2}B}
Divide both sides by B.
S=\frac{16\left(25x-1\right)^{2}}{25\left(20x-1\right)^{2}B}
Dividing by B undoes the multiplication by B.
S=\frac{16\left(25x-1\right)^{2}}{25B\left(20x-1\right)^{2}}
Divide \frac{16\left(25x-1\right)^{2}}{25\left(20x-1\right)^{2}} by B.