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Solve for B, C
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68C=12
Consider the second equation. Insert the known values of variables into the equation.
C=\frac{12}{68}
Divide both sides by 68.
C=\frac{3}{17}
Reduce the fraction \frac{12}{68} to lowest terms by extracting and canceling out 4.
B=68 C=\frac{3}{17}
The system is now solved.