Solve for B
B=1
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B≔1
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B=6-6\left(\frac{3}{6}+\frac{2}{6}\right)
Least common multiple of 2 and 3 is 6. Convert \frac{1}{2} and \frac{1}{3} to fractions with denominator 6.
B=6-6\times \frac{3+2}{6}
Since \frac{3}{6} and \frac{2}{6} have the same denominator, add them by adding their numerators.
B=6-6\times \frac{5}{6}
Add 3 and 2 to get 5.
B=6-5
Cancel out 6 and 6.
B=1
Subtract 5 from 6 to get 1.
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