Solve for B
B=\left(4-3x\right)^{2}
Solve for x (complex solution)
x=\frac{\sqrt{B}+4}{3}
x=\frac{-\sqrt{B}+4}{3}
Solve for x
x=\frac{\sqrt{B}+4}{3}
x=\frac{-\sqrt{B}+4}{3}\text{, }B\geq 0
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B=16-24x+9x^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(4-3x\right)^{2}.
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