Solve for B
B=\left(2x+7\right)\left(x-3\right)^{2}
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B=\left(2x+7\right)\left(x^{2}-6x+9\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
B=2x^{3}-5x^{2}-24x+63
Use the distributive property to multiply 2x+7 by x^{2}-6x+9 and combine like terms.
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