Solve B=-3+1/3/1+frac{1{3}}

$$B = \frac { - 3 + \frac { 1 } { 3 } } { 1 + \frac { 1 } { 3 } }$$

Solve for B

$$B=-2$$

Steps for Solving Linear Equation

Convert -3 to fraction -\frac{9}{3}.

$$B=\frac{-\frac{9}{3}+\frac{1}{3}}{1+\frac{1}{3}}$$

Since -\frac{9}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$B=\frac{\frac{-9+1}{3}}{1+\frac{1}{3}}$$

Add -9 and 1 to get -8.

$$B=\frac{-\frac{8}{3}}{1+\frac{1}{3}}$$

Convert 1 to fraction \frac{3}{3}.

$$B=\frac{-\frac{8}{3}}{\frac{3}{3}+\frac{1}{3}}$$

Since \frac{3}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$B=\frac{-\frac{8}{3}}{\frac{3+1}{3}}$$

Add 3 and 1 to get 4.

$$B=\frac{-\frac{8}{3}}{\frac{4}{3}}$$

Divide -\frac{8}{3} by \frac{4}{3} by multiplying -\frac{8}{3} by the reciprocal of \frac{4}{3}.

$$B=-\frac{8}{3}\times \frac{3}{4}$$

Multiply -\frac{8}{3} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$B=\frac{-8\times 3}{3\times 4}$$

Cancel out 3 in both numerator and denominator.

$$B=\frac{-8}{4}$$

Divide -8 by 4 to get -2.

$$B=-2$$

Assign B

$$B≔-2$$