Solve for A
A=4B-2C+16
Solve for B
B=\frac{A+2C-16}{4}
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A+2C=16+4B
Add 4B to both sides.
A=16+4B-2C
Subtract 2C from both sides.
-4B+2C=16-A
Subtract A from both sides.
-4B=16-A-2C
Subtract 2C from both sides.
-4B=16-2C-A
The equation is in standard form.
\frac{-4B}{-4}=\frac{16-2C-A}{-4}
Divide both sides by -4.
B=\frac{16-2C-A}{-4}
Dividing by -4 undoes the multiplication by -4.
B=\frac{A}{4}+\frac{C}{2}-4
Divide 16-A-2C by -4.
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