Solve Ad=2x^2+12x+10

$$A d = 2 x ^ { 2 } + 12 x + 10$$

Solve for A (complex solution)

$$\left\{\begin{matrix}A=\frac{2\left(x+1\right)\left(x+5\right)}{d}\text{, }&d\neq 0\\A\in \mathrm{C}\text{, }&\left(x=-1\text{ or }x=-5\right)\text{ and }d=0\end{matrix}\right.$$

Steps for Solving Linear Equation

The equation is in standard form.

$$dA=2x^{2}+12x+10$$

Divide both sides by d.

$$\frac{dA}{d}=\frac{2\left(x+1\right)\left(x+5\right)}{d}$$

Dividing by d undoes the multiplication by d.

$$A=\frac{2\left(x+1\right)\left(x+5\right)}{d}$$

Solve for d (complex solution)

$$\left\{\begin{matrix}d=\frac{2\left(x+1\right)\left(x+5\right)}{A}\text{, }&A\neq 0\\d\in \mathrm{C}\text{, }&\left(x=-1\text{ or }x=-5\right)\text{ and }A=0\end{matrix}\right.$$

Steps for Solving Linear Equation

The equation is in standard form.

$$Ad=2x^{2}+12x+10$$

Divide both sides by A.

$$\frac{Ad}{A}=\frac{2\left(x+1\right)\left(x+5\right)}{A}$$

Dividing by A undoes the multiplication by A.

$$d=\frac{2\left(x+1\right)\left(x+5\right)}{A}$$

Solve for A

$$\left\{\begin{matrix}A=\frac{2\left(x+1\right)\left(x+5\right)}{d}\text{, }&d\neq 0\\A\in \mathrm{R}\text{, }&\left(x=-1\text{ or }x=-5\right)\text{ and }d=0\end{matrix}\right.$$

Steps for Solving Linear Equation

The equation is in standard form.

$$dA=2x^{2}+12x+10$$

Divide both sides by d.

$$\frac{dA}{d}=\frac{2\left(x+1\right)\left(x+5\right)}{d}$$

Dividing by d undoes the multiplication by d.

$$A=\frac{2\left(x+1\right)\left(x+5\right)}{d}$$

Solve for d

$$\left\{\begin{matrix}d=\frac{2\left(x+1\right)\left(x+5\right)}{A}\text{, }&A\neq 0\\d\in \mathrm{R}\text{, }&\left(x=-1\text{ or }x=-5\right)\text{ and }A=0\end{matrix}\right.$$

Steps for Solving Linear Equation

The equation is in standard form.

$$Ad=2x^{2}+12x+10$$

Divide both sides by A.

$$\frac{Ad}{A}=\frac{2\left(x+1\right)\left(x+5\right)}{A}$$

Dividing by A undoes the multiplication by A.

$$d=\frac{2\left(x+1\right)\left(x+5\right)}{A}$$