Solve for A (complex solution)
\left\{\begin{matrix}A=-\frac{C-2B}{X}\text{, }&X\neq 0\\A\in \mathrm{C}\text{, }&B=\frac{C}{2}\text{ and }X=0\end{matrix}\right.
Solve for A
\left\{\begin{matrix}A=-\frac{C-2B}{X}\text{, }&X\neq 0\\A\in \mathrm{R}\text{, }&B=\frac{C}{2}\text{ and }X=0\end{matrix}\right.
Solve for B
B=\frac{AX+C}{2}
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XA=2B-C
The equation is in standard form.
\frac{XA}{X}=\frac{2B-C}{X}
Divide both sides by X.
A=\frac{2B-C}{X}
Dividing by X undoes the multiplication by X.
XA=2B-C
The equation is in standard form.
\frac{XA}{X}=\frac{2B-C}{X}
Divide both sides by X.
A=\frac{2B-C}{X}
Dividing by X undoes the multiplication by X.
2B-C=AX
Swap sides so that all variable terms are on the left hand side.
2B=AX+C
Add C to both sides.
\frac{2B}{2}=\frac{AX+C}{2}
Divide both sides by 2.
B=\frac{AX+C}{2}
Dividing by 2 undoes the multiplication by 2.
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