Solve for A
A=\frac{7}{BT}
B\neq 0\text{ and }T\neq 0
Solve for B
B=\frac{7}{AT}
T\neq 0\text{ and }A\neq 0
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BTA=7
The equation is in standard form.
\frac{BTA}{BT}=\frac{7}{BT}
Divide both sides by TB.
A=\frac{7}{BT}
Dividing by TB undoes the multiplication by TB.
ATB=7
The equation is in standard form.
\frac{ATB}{AT}=\frac{7}{AT}
Divide both sides by AT.
B=\frac{7}{AT}
Dividing by AT undoes the multiplication by AT.
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