Solve AC=sqrt{(-3-(-1))^2+(3-(-3))^2}

$$A C = \sqrt { ( - 3 - ( - 1 ) ) ^ { 2 } + ( 3 - ( - 3 ) ) ^ { 2 } }$$

Solve for A

$$A=\frac{2\sqrt{10}}{C}$$

$$C\neq 0$$

Steps for Solving Linear Equation

The opposite of -1 is 1.

$$AC=\sqrt{\left(-3+1\right)^{2}+\left(3-\left(-3\right)\right)^{2}}$$

Add -3 and 1 to get -2.

$$AC=\sqrt{\left(-2\right)^{2}+\left(3-\left(-3\right)\right)^{2}}$$

Calculate -2 to the power of 2 and get 4.

$$AC=\sqrt{4+\left(3-\left(-3\right)\right)^{2}}$$

The opposite of -3 is 3.

$$AC=\sqrt{4+\left(3+3\right)^{2}}$$

Add 3 and 3 to get 6.

$$AC=\sqrt{4+6^{2}}$$

Calculate 6 to the power of 2 and get 36.

$$AC=\sqrt{4+36}$$

Add 4 and 36 to get 40.

$$AC=\sqrt{40}$$

Factor 40=2^{2}\times 10. Rewrite the square root of the product \sqrt{2^{2}\times 10} as the product of square roots \sqrt{2^{2}}\sqrt{10}. Take the square root of 2^{2}.

$$AC=2\sqrt{10}$$

The equation is in standard form.

$$CA=2\sqrt{10}$$

Divide both sides by C.

$$\frac{CA}{C}=\frac{2\sqrt{10}}{C}$$

Dividing by C undoes the multiplication by C.

$$A=\frac{2\sqrt{10}}{C}$$

Solve for C

$$C=\frac{2\sqrt{10}}{A}$$

$$A\neq 0$$

Steps for Solving Linear Equation

The opposite of -1 is 1.

$$AC=\sqrt{\left(-3+1\right)^{2}+\left(3-\left(-3\right)\right)^{2}}$$

Add -3 and 1 to get -2.

$$AC=\sqrt{\left(-2\right)^{2}+\left(3-\left(-3\right)\right)^{2}}$$

Calculate -2 to the power of 2 and get 4.

$$AC=\sqrt{4+\left(3-\left(-3\right)\right)^{2}}$$

The opposite of -3 is 3.

$$AC=\sqrt{4+\left(3+3\right)^{2}}$$

Add 3 and 3 to get 6.

$$AC=\sqrt{4+6^{2}}$$

Calculate 6 to the power of 2 and get 36.

$$AC=\sqrt{4+36}$$

Add 4 and 36 to get 40.

$$AC=\sqrt{40}$$

Factor 40=2^{2}\times 10. Rewrite the square root of the product \sqrt{2^{2}\times 10} as the product of square roots \sqrt{2^{2}}\sqrt{10}. Take the square root of 2^{2}.

$$AC=2\sqrt{10}$$

Divide both sides by A.

$$\frac{AC}{A}=\frac{2\sqrt{10}}{A}$$

Dividing by A undoes the multiplication by A.

$$C=\frac{2\sqrt{10}}{A}$$