Solve for A
\left\{\begin{matrix}A=-\frac{7C-102}{B}\text{, }&B\neq 0\\A\in \mathrm{R}\text{, }&C=\frac{102}{7}\text{ and }B=0\end{matrix}\right.
Solve for B
\left\{\begin{matrix}B=-\frac{7C-102}{A}\text{, }&A\neq 0\\B\in \mathrm{R}\text{, }&C=\frac{102}{7}\text{ and }A=0\end{matrix}\right.
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AB=102-7C
Subtract 7C from both sides.
BA=102-7C
The equation is in standard form.
\frac{BA}{B}=\frac{102-7C}{B}
Divide both sides by B.
A=\frac{102-7C}{B}
Dividing by B undoes the multiplication by B.
AB=102-7C
Subtract 7C from both sides.
\frac{AB}{A}=\frac{102-7C}{A}
Divide both sides by A.
B=\frac{102-7C}{A}
Dividing by A undoes the multiplication by A.
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